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System 4 of 6 TS As seen from the title already can see, this applies to me like and quite successfully used a system known roulette Act: Two-thirds of the amazing Act. It states that, for example, of 36 Plein figures about 24 (in one, two more or less, it is not) a long time, constantly appear during 12 points inevitable. Why this is so, until now has not explained. The fact that it is to a fact, can demonstrate exactly. And not only in Plein the numbers, but also in all other opportunities (dozens, Columns, etc.) The system will be presented the two-thirds of the law Transversals Alen Simple. Since it is exactly 6 TS, it can wonderful. The 6 transversals Alen Simple are as follows: 1 to 6 = Transversal Simple 1

7-12 = Transversal Simple 2 13-18 = Transversal Simple 3 19-24 = Transversal Simple 4 25-30 = Transversal Simple 5 31-36 = Transversal Simple 6 After the two-thirds Act appear transversals Alen 4 (2 / 3) temporarily more often than the other two. How to find out what these are? Now, through an entirely simple booking system, which follows follows: Apart from any fallen figure is the corresponding number TS-written, 5 = 1 26 = 5 6 = 1 10 = 2 and so on. Next step: when a number within Simple Transversal the last 4 coup appeared twice, this is underlined (in above example would be the 1). This will continue as long as until: After the last point underlined TS-row 4 different TS numbers. Then you can be set. And on this last 4 different transversals Alen Simple. For example according to the permanence of Table 1 of the casino

Total Plus remains. After the second sentence in each case canceled, even in loss. To compensate a row after two Fehltreffern you can now short (2-3 Coups) with the basic bet double play. Another tip: Always leave at least 2 neighboring transversals Alen together, either to a dozen or 3 neighbours even Manque / passports. So too in our o.g. Example: The transversals Alen 4, 5 and 6 Passe cover exactly the figures, so that you necessarily Passe should show (of course with 3 pieces). The profit result is in the same, but in the presence of Zero, you have a great advantage because namely the use is not lost, but initially blocked. Now you can share with the bank or wait for the next roll. If this positive out, the total use again. The summary of dozens does not benefit (by the way, you should see also Free Slots and Free Poker) as Passe / Manque, but it increases the clarity of your bets. In addition, profits in case the rapid disbursement. In case of 0 (zero), the 4 identified Alen still transversals nachgesetzt once. Successful I mostly played the following options: I have geschilderte by posting the top rate signal identified, but is not set, but wait, if the first sentence may fail. Was this is the case, I actually set and won mainly because a double loss rate is not so common. You can also drive to the top and see whether a negative balance (-2 Or -8) has occurred. As experience shows two minus row also are rare, it is only when preceded by a minus balance. "4 of 6 TS" can also play a progression, making the self-imposed daily piece profit target is achieved much faster. In about 85 percent of the manner determined by the above sentence is occasions Progression not necessary because one of the four taken immediately set TS In about 10 percent of cases, one of the four set TS with the second Coup. Approximately 4 percent of the average value of meeting with the 3rd Coup. Less than 1 percent of the value for even later meeting. The progression factor is 3: 1st Progression Level 4 x 1 = pieces 4 pieces = total 4 pieces (Profit: +2) 2nd Progression Level 4 x 3 = 12 pieces pieces = 16 total pieces (Profit: +2) 3rd Progression Level 4 x 9 pieces = 36 pieces = 52 total pieces (Profit: +2) 4th Progression level: 4 x 27 pieces = 108 pieces = 160 pieces total (Profit: +2)

Now I am either proceed as follows: The 1st and 2 Progression stage I at the same table, and so that on average 95% of cases won. If the 2nd Progression level also failed, I have to top dargestelltem booking process after the next sentence opportunity Kept out (whether at the same table or at any of the other is secondary) and then there with the 3rd Progression level continue. At 85% was now the desired hit, with 95% probability but the next coup. If it seems too dangerous, 160 pieces of risk can also Variant apply: 1st Progression Level 4 x 1 piece = 4 = pieces 4 pieces total (profit: +2) 2nd Progression Level 4 x 3 = 12 pieces pieces = 16 pieces total (profit: +2) but then: 3rd Progression Level 4 x 4 pieces = 16 pieces = 32 pieces total In the case of profit achieved 8 pieces of surplus and has only a total of 8 pieces minus (the 16 lost pieces progression from Level 1 and 2 8 pieces less profit from Level 3). The next profit coup - the 4x4 with set pieces - is the temporary loss egalisiert again. If the progression Level 3 but failed tripled again: 4th Progression Level 4 x 12 pieces = 48 pieces = 80 pieces total In the case of profit achieved 8 pieces of surplus and has only a total of 8 pieces minus (the 72 lost pieces progression from Level 1, 2 and 3 8 pieces less profit from Level 4). The next profit coup, with 4x4 pieces is legible the temporary loss egalisiert again. For every 100 Coups per table with a profit of about 6 pieces can be expected. In other words, about 2 per hour pieces Profit. The accounting system is easy for several tables at the same time note so that constantly changing tables can be, resulting in increased profits per hour.